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2a^2-24+13a=0
a = 2; b = 13; c = -24;
Δ = b2-4ac
Δ = 132-4·2·(-24)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-19}{2*2}=\frac{-32}{4} =-8 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+19}{2*2}=\frac{6}{4} =1+1/2 $
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